Tsotsobe claims four wickets, India bowled out for 190By IANS
Saturday, January 15, 2011
JOHANNESBURG - South African pacer Lonwabo Tsotsobe claimed four wickets, triggering an Indian collapse that saw the visitors being bowled out for 190 in their second One-day International cricket encounter here Saturday.
After their poor performance in the first ODI at Durban, Indian batsmen again came a cropper against a disciplined South African pace attack and folded up in 47.2 overs.
Yuvraj Singh (53) and Mahendra Singh Dhoni (38) shared an 83-run stand, but after the stylish left-hander was dismissed by Tsotsobe, it was a march down to the pavilion. The last seven wickets fell for 40 runs.
Left-arm pacer Tsotsobe (4-22) registered his best ODI figure.
After captain Dhoni elected to bat, India lost Murali Vijay (16) early with Tsotsobe claiming his first wicket.
Dale Steyn (2-35) and Tsotsobe got good purchase from the track with the new ball. Virat Kohli (22) was run out and Sachin Tendulkar (24) was bowled by spinner Johan Botha with the ball keeping low.
Yuvraj looked in good touch and stroked four fours while Dhoni also played with ease. The two focussed on building a partnership.
But Tsotsobe dismissed Yuvraj caught by Steyn at mid-off and then trapped Suresh Raina (11) lbw. He then cleaned up Dhoni with a slower ball.
Morne Morkel (2-32) got the wicket of Rohit Sharma and the tail did not provide any resistance as they went slogging and gave up their wickets.